clc
clear all

%% Example 1 with for-end and break
disp('Example 1 - The break statement')
% The loop below will calculate values of k^2-50
% for all values of the requested k until k^2-50 turns negative
for k=-10:1:10
    if (k^2-50<0)
        break
    end
    val=k^2-50;
    fprintf('  k=%g  val=%g\n',k,val)
end
disp(' ')

%% Example 1 with while-end
disp('Example 1: With the while-end loop')
% using the while-end loop to do the same thing as above
k=-10;
while (k<=10) & (k^2-50>0)
    val=k^2-50;
    fprintf('  k=%g val=%g\n',k,val)
    k=k+1;
end
disp(' ')

%% Example 2 with for-end and continue
disp('Example 2 - The continue statement')
% The loop below will calculate values of k^2-50
% for all values of the requested k and output only the postive values
for k=-10:1:10
    if (k^2-50<0)
        continue
    end
    val=k^2-50;
    fprintf('  k=%g  val=%g\n',k,val)
end